Web20 sep. 2024 · Brainly User. H2O is the formula for Water. Molecular mass = 2 (H)+1 (O) = 2*1 + 1*16 = 2 + 16 = 18 gm. 1 gm molecule of water = 18 g of water. 18gm of water … WebGet more out of your subscription* Access to over 100 million course-specific study resources; 24/7 help from Expert Tutors on 140+ subjects; Full access to over 1 million Textbook Solutions
How many hydrogen atoms are present in 36g of water? - Quora
WebMg3N2 + 6H20 --> 3 Mg(OH)2 + 2NH3, When 2.00 moles of H20 react, how many grams of NH3 are produced? The molar mass of NH3 is 17.04 g/mole. Select one: a. 5.68 b. 34.1 O c. 17.1 d. 22.7 O e. 11.4 ; This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Web18 apr. 2024 · The SI base unit for amount of substance is the mole. 1 grams Glucose is equal to 0.0055507486072617 mole. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between grams Glucose and mole. Type in your own numbers in the form to convert the units! sign of slash
What is the total number of atoms present in 36 grams of water?
WebThat means that in one mole of water, there are N A water molecules. 1 mole of water = 18 grams. no. of moles = givenmass molarmass = 36 18=2. Hence,36 grams of water has two moles of water. No. of molecules = No. of moles ×Avagadrono. = 2×6.022×1023 = 12.044×1023. Suggest Corrections. Web20 sep. 2024 · H2O is the formula for Water. Molecular mass = 2 (H)+1 (O) = 2*1 + 1*16 = 2 + 16 = 18 gm 1 gm molecule of water = 18 g of water. 18gm of water contain 6.023 x 10^23 molecules of water For 36 gm of water contain 36x 6.023 x 10^23/18 = 2 x 6.023 x 10^23 molecules of water 2x6.023x10^23 molecules of water ^-^ umm.. but its not 46 its … Web25 mrt. 2024 · Okay, so for home work i was given this problem. Suppose that 8.00g of CH4 reacts with 16.00g O2 to form CO2 and H2O, find the grams of CH4, H2o, and O2 left over. Balanced Equation : CH4 + 2O2 = CO2 + 2H2O. My Calculations for limiting Reagent: 8.00g CH4 (1 mol CH4/16.04g CH4) (2 mol H2O/1 mol CH4) (18.01g/1 mol H2O) = 18.0g H2O. sign of slience